{"id":2117,"date":"2022-10-20T12:47:53","date_gmt":"2022-10-20T12:47:53","guid":{"rendered":"https:\/\/blog.praxilabs.com\/?p=2117"},"modified":"2025-10-19T18:44:13","modified_gmt":"2025-10-19T18:44:13","slug":"free-body-diagram-path-object-motion","status":"publish","type":"post","link":"https:\/\/praxilabs.com\/en\/blog\/2022\/10\/20\/free-body-diagram-path-object-motion\/","title":{"rendered":"Free-Body Diagrams\u2013 How to Exclusively Chart the Path of an Object\u2019s motion"},"content":{"rendered":"<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">Have you ever wondered how physicists create free-body diagrams? What about economists or biologists? All of these professionals use specific symbols to chart the motion of an object.<\/span><\/p>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">The importance and virality of free-body diagrams (FBD) in physics are beyond description. Free-body diagrams emerged since Newton\u2019s laws of motion stretched out to include many forms of dynamic and static motion. Such diagrams can vary in their level of simplicity. Some diagrams may be very simple, while others can be very sophisticated, need special treatment and undergo many steps.<\/span><\/p>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">A free-body diagram is a tool that is incredibly useful to visually chart the path an object will take under different circumstances. By understanding how external forces influence movement, you can improve your predictions and problem-solving skills.<\/span><\/p>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">We will start by defining what an FBD is and then explore some real-world examples. Finally, we will look at some tips for creating effective FBDs. After reading this blog, you should have a basic understanding of how to approach problems that require FBDs and be able to diagram simple motions accurately&#8230; Let\u2019s take a closer look!<\/span><\/p>\n<p style=\"text-align: center;\"><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><strong><a class=\"maxbutton-3 maxbutton\" href=\"https:\/\/praxilabs.com\/en\/pricing\"><span class='mb-text'>Check Praxilabs Virtual labs Plans<\/span><\/a><\/strong><\/span><\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_83 counter-hierarchy ez-toc-counter ez-toc-light-blue ez-toc-container-direction\">\r\n<div class=\"ez-toc-title-container\">\r\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\r\n<span class=\"ez-toc-title-toggle\"><\/span><\/div>\r\n<nav><ul class='ez-toc-list ez-toc-list-level-1 ' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/praxilabs.com\/en\/blog\/2022\/10\/20\/free-body-diagram-path-object-motion\/#Free-Body_Diagram_Definition\" >Free-Body Diagram Definition<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/praxilabs.com\/en\/blog\/2022\/10\/20\/free-body-diagram-path-object-motion\/#Purpose_of_Free-Body_Diagram\" >Purpose of Free-Body Diagram<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/praxilabs.com\/en\/blog\/2022\/10\/20\/free-body-diagram-path-object-motion\/#Free-Body_Diagram_Examples\" >Free-Body Diagram Examples<\/a><ul class='ez-toc-list-level-3' ><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/praxilabs.com\/en\/blog\/2022\/10\/20\/free-body-diagram-path-object-motion\/#Example_1_A_Book_on_a_Table\" >Example 1: A Book on a Table<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/praxilabs.com\/en\/blog\/2022\/10\/20\/free-body-diagram-path-object-motion\/#Example_2_A_Car_Accelerating_Down_a_Road\" >Example 2: A Car Accelerating Down a Road<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/praxilabs.com\/en\/blog\/2022\/10\/20\/free-body-diagram-path-object-motion\/#How_to_Draw_an_Effective_Free-Body_Diagram\" >How to Draw an Effective Free-Body Diagram?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/praxilabs.com\/en\/blog\/2022\/10\/20\/free-body-diagram-path-object-motion\/#Free-Body_Diagram_Problems_and_Solutions\" >Free-Body Diagram Problems and Solutions<\/a><ul class='ez-toc-list-level-3' ><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/praxilabs.com\/en\/blog\/2022\/10\/20\/free-body-diagram-path-object-motion\/#Problem_1\" >Problem 1<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/praxilabs.com\/en\/blog\/2022\/10\/20\/free-body-diagram-path-object-motion\/#Problem_2\" >Problem 2<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/praxilabs.com\/en\/blog\/2022\/10\/20\/free-body-diagram-path-object-motion\/#Advantages_of_Free-Body_Diagrams\" >Advantages of Free-Body Diagrams<\/a><\/li><\/ul><\/nav><\/div>\r\n<h2><span class=\"ez-toc-section\" id=\"Free-Body_Diagram_Definition\"><\/span><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><b>Free-Body Diagram Definition<\/b><\/span><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">A free-body diagram is<\/span><\/p>\n<p style=\"text-align: center;\"><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b><i>\u201ca graphical representation of the physical forces acting on an object.\u201d<\/i><\/b><\/span><\/p>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">This includes both external forces (gravity, friction, wind, etc.) and internal forces (muscles, tendons, etc.). FBDs are used by physicists to simplify complex problems and understand the underlying physics at work.<\/span><\/p>\n<p><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"size-medium wp-image-2113 aligncenter\" src=\"https:\/\/praxilabs.com\/en\/blog\/wp-content\/uploads\/2022\/10\/free-body-diagram-illustration-300x169.jpeg\" alt=\"illustration of free-body diagram\" width=\"300\" height=\"169\" srcset=\"https:\/\/praxilabs.com\/en\/blog\/wp-content\/uploads\/2022\/10\/free-body-diagram-illustration-300x169.jpeg 300w, https:\/\/praxilabs.com\/en\/blog\/wp-content\/uploads\/2022\/10\/free-body-diagram-illustration-1024x576.jpeg 1024w, https:\/\/praxilabs.com\/en\/blog\/wp-content\/uploads\/2022\/10\/free-body-diagram-illustration-768x432.jpeg 768w, https:\/\/praxilabs.com\/en\/blog\/wp-content\/uploads\/2022\/10\/free-body-diagram-illustration-1536x864.jpeg 1536w, https:\/\/praxilabs.com\/en\/blog\/wp-content\/uploads\/2022\/10\/free-body-diagram-illustration.jpeg 1920w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/span><\/p>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">When creating an FBD, it is important to consider all of the forces that are acting on an object. This can be daunting, but some tricks can help. First, think about whether the object is in contact with anything else. These objects will experience forces due to friction or contact with other objects. Second, think about any fluids that the object may be interacting with. This could include air resistance or fluid drag. Finally, think about the object\u2019s mass and the force of gravity. These are the internal forces that will be acting on the object.<\/span><\/p>\n<h2><span class=\"ez-toc-section\" id=\"Purpose_of_Free-Body_Diagram\"><\/span><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><b>Purpose of Free-Body Diagram<\/b><\/span><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">Physical contact between objects, while non-contact forces can act on an object without any physical contact. The most common type of contact force is friction, which arises when two surfaces rub against each other. Other examples of contact forces include tension (the force exerted by a rope or string), the normal force (the force exerted by a surface on an object), and air resistance (the force exerted by the air on an object).<\/span><\/p>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">Non-contact forces, on the other hand, do not require physical contact between objects. The most common type of non-contact force is gravity, which attracts objects towards the center of the Earth. Other examples of non-contact forces include magnetic and electrostatic forces. Once all external forces acting on the object have been identified, they can be represented using arrows on the FBD. The direction of each arrow should correspond to the direction in which the force is acting, and the length of the arrow should be proportional to the magnitude of the force.<\/span><\/p>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">In addition to external forces, FBDs also include information about the object itself, such as its mass and velocity. This information is generally conveyed through text or symbols placed near the object on the diagram. Free-body diagrams are a powerful tool for understanding the motion of objects. They allow us to see all of the forces acting on an object and to visualize how these forces affect its motion.<\/span><\/p>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">Once you have considered all of the forces that are acting on an object, you can begin to create your FBD. The first step is to sketch the object in question. This should be a simple representation of the object, including all relevant dimensions. Next, you will need to add arrows to represent the direction and magnitude of each force. The length of the arrow should be proportional to the strength of the force. Finally, label each force accordingly.<\/span><\/p>\n<p style=\"text-align: center;\"><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><strong>Try Praxilabs&#8217; <a href=\"https:\/\/praxilabs.com\/en\/virtual-physics-lab\">Virtual Physics Lab<\/a> to test Free-Body simulations<\/strong><\/span><\/p>\n<p style=\"text-align: center;\"><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><strong><a class=\"maxbutton-3 maxbutton\" href=\"https:\/\/praxilabs.com\/en\/sign-up\"><span class='mb-text'>Create a Free Account To Our Free Virtual Experiments<\/span><\/a><\/strong><\/span><\/p>\n<h2><span class=\"ez-toc-section\" id=\"Free-Body_Diagram_Examples\"><\/span><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><b>Free-Body Diagram Examples<\/b><\/span><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">Now that we have covered <a href=\"https:\/\/www.youtube.com\/watch?v=52R61aSWHg0\" target=\"_blank\" rel=\"noopener\">the basics of free-body diagrams<\/a>, let\u2019s look at some real-world examples.<\/span><\/p>\n<h3><span class=\"ez-toc-section\" id=\"Example_1_A_Book_on_a_Table\"><\/span><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><b>Example 1: A Book on a Table<\/b><\/span><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">Let\u2019s say you have a book on a table. The book is not moving, so we know that the net force acting on the book must be zero. This means that the sum of all the forces acting on the book must be zero. In this case, only two forces are acting on the book: gravity and the force exerted by the table. We can represent this with the following free-body diagram.<\/span><\/p>\n<p><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><img loading=\"lazy\" decoding=\"async\" class=\" wp-image-2118 aligncenter\" src=\"https:\/\/praxilabs.com\/en\/blog\/wp-content\/uploads\/2022\/10\/free-body-diagram-and-resultant-force-book-example-300x110.jpg\" alt=\"free-body diagram of a book and a table\" width=\"453\" height=\"166\" srcset=\"https:\/\/praxilabs.com\/en\/blog\/wp-content\/uploads\/2022\/10\/free-body-diagram-and-resultant-force-book-example-300x110.jpg 300w, https:\/\/praxilabs.com\/en\/blog\/wp-content\/uploads\/2022\/10\/free-body-diagram-and-resultant-force-book-example-768x283.jpg 768w, https:\/\/praxilabs.com\/en\/blog\/wp-content\/uploads\/2022\/10\/free-body-diagram-and-resultant-force-book-example.jpg 940w\" sizes=\"auto, (max-width: 453px) 100vw, 453px\" \/><\/span><\/p>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">As you can see, the arrows representing gravity and the force exerted by the table cancel each other out. This is because they are pointing in opposite directions and have equal magnitudes. We can also see that the magnitude of these forces is equal to the weight of the book.<\/span><\/p>\n<h3><span class=\"ez-toc-section\" id=\"Example_2_A_Car_Accelerating_Down_a_Road\"><\/span><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><b>Example 2: A Car Accelerating Down a Road<\/b><\/span><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><span style=\"font-weight: 400;\">Now, let\u2019s look at a more complicated example. Consider a car that is driving down a road. The car has a mass of 1000 kg and is accelerating at 2 m\/s<\/span><sup><span style=\"font-weight: 400;\">2<\/span><\/sup><span style=\"font-weight: 400;\">. We can represent this with the following free-body diagram.<\/span><\/span><\/p>\n<p><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><img loading=\"lazy\" decoding=\"async\" class=\"size-medium wp-image-2115 aligncenter\" src=\"https:\/\/praxilabs.com\/en\/blog\/wp-content\/uploads\/2022\/10\/free-body-diagram-car-slowing-down-274x300.jpg\" alt=\"a slowing down car as an example of free-body diagrams\" width=\"274\" height=\"300\" srcset=\"https:\/\/praxilabs.com\/en\/blog\/wp-content\/uploads\/2022\/10\/free-body-diagram-car-slowing-down-274x300.jpg 274w, https:\/\/praxilabs.com\/en\/blog\/wp-content\/uploads\/2022\/10\/free-body-diagram-car-slowing-down.jpg 555w\" sizes=\"auto, (max-width: 274px) 100vw, 274px\" \/><\/span><\/p>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">As you can see, the car is being acted upon by four forces: gravity, friction, the force exerted by the road, and the force exerted by the engine. The force exerted by the road is pointing in the same direction as the motion of the car, so we know it is responsible for acceleration. The other three forces are all pointing in directions opposite to that of motion and are thus slowing down the car.<\/span><\/p>\n<h2><span class=\"ez-toc-section\" id=\"How_to_Draw_an_Effective_Free-Body_Diagram\"><\/span><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><b>How to Draw an Effective Free-Body Diagram?<\/b><\/span><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">Now, let\u2019s look at some tips for creating effective free-body diagrams.<\/span><\/p>\n<ol>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>Keep it Simple<\/b><b><br \/>\n<\/b><span style=\"font-weight: 400;\">Free-body diagrams can quickly become cluttered and confusing. When creating an FBD, only include the forces that are relevant to the problem at hand. This will make your diagram much easier to interpret.<\/span><\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>Use Appropriate Units<\/b><b><br \/>\n<\/b><span style=\"font-weight: 400;\">When labeling your forces, be sure to use appropriate units. This will help you keep track of the magnitudes of the forces and make sure they are consistent with one another.<\/span><\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>Pay Attention to Direction<\/b><b><br \/>\n<\/b><span style=\"font-weight: 400;\">The direction of the forces is just as important as the magnitude. Be sure to include arrows in your diagram to indicate the direction of each force.<\/span><\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>Label Your Forces<\/b><b><br \/>\n<\/b><span style=\"font-weight: 400;\">It is important to label each force in your diagram. This will help you keep track of the different forces acting on the object and make sure they are all accounted for.<\/span><\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>Check Your Work<\/b><b><br \/>\n<\/b><span style=\"font-weight: 400;\">Once you have created your free-body diagram, take a step back and check your work. Make sure that all of the forces are accounted for and that they are labeled correctly. This will help you avoid making mistakes when solving problems.<\/span><\/span><\/li>\n<\/ol>\n<h2><span class=\"ez-toc-section\" id=\"Free-Body_Diagram_Problems_and_Solutions\"><\/span><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><b>Free-Body Diagram Problems and Solutions<\/b><\/span><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">Now that we have covered the basics of free-body diagrams, let\u2019s put what we\u2019ve learned into practice with <a href=\"https:\/\/www.youtube.com\/watch?v=3rZR7FSSidc\" target=\"_blank\" rel=\"noopener\">some problems<\/a>.<\/span><\/p>\n<h3><span class=\"ez-toc-section\" id=\"Problem_1\"><\/span><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><b>Problem 1<\/b><\/span><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><span style=\"font-weight: 400;\">A car is driving down a road. The car has a mass of 1000 kg and is accelerating at 2 m\/s<\/span><sup><span style=\"font-weight: 400;\">2<\/span><\/sup><span style=\"font-weight: 400;\">. Four forces are acting on the car: gravity, the force exerted by the road, friction, and the force exerted by the engine. <\/span><b>What is the magnitude of each force?<\/b><\/span><\/p>\n<p><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>Solution<\/b><\/span><\/p>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">First, let\u2019s create a free-body diagram of the situation.<\/span><\/p>\n<p><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><span style=\"font-weight: 400;\">As we can see, four forces are acting on the car. We know that the car has a mass of 1000 kg and is accelerating at 2 m\/s<\/span><span style=\"font-weight: 400;\">2<\/span><span style=\"font-weight: 400;\">. This means that the sum of the forces must be equal to the mass of the car times the acceleration.<\/span><\/span><\/p>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">Now, let\u2019s label each force and write down the equations we need to solve for each one:<\/span><\/p>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>Gravity<\/b><\/span><\/li>\n<\/ul>\n<p style=\"text-align: center;\"><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><strong><span style=\"font-size: 14pt;\">F<sub>g<\/sub> = m*g<\/span><\/strong><\/span><\/p>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>Force exerted by the road<\/b><\/span><\/li>\n<\/ul>\n<p style=\"text-align: center;\"><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><strong><span style=\"font-size: 14pt;\">F<sub>r <\/sub>= m*a<\/span><\/strong><\/span><\/p>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>Friction<\/b><\/span><\/li>\n<\/ul>\n<p style=\"text-align: center;\"><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><strong><span style=\"font-size: 14pt;\">F<sub>f<\/sub> = \u00b5N<\/span><\/strong><\/span><\/p>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>Force exerted by the engine<\/b><\/span><\/li>\n<\/ul>\n<p style=\"text-align: center;\"><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><strong><span style=\"font-size: 14pt;\">F<sub>e<\/sub> = m*a<\/span><\/strong><\/span><\/p>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">where<\/span><\/p>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>m:<\/b><span style=\"font-weight: 400;\"> the mass of the car.<\/span><\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>g: <\/b><span style=\"font-weight: 400;\">the acceleration due to gravity.<\/span><\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>a:<\/b><span style=\"font-weight: 400;\"> the acceleration.<\/span><\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>\u00b5:<\/b><span style=\"font-weight: 400;\"> the coefficient of friction.<\/span><\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>N:<\/b><span style=\"font-weight: 400;\"> the normal force.<\/span><\/span><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">To solve for these forces, we will need to know the values of m, a, \u00b5, and N. We are given m and a, but we will need to calculate \u00b5 and N. The coefficient of friction can be found using the following equation:<\/span><\/p>\n<p style=\"text-align: center;\"><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><strong><span style=\"font-size: 14pt;\">\u00b5 = F<sub>f<\/sub>\/N<\/span><\/strong><\/span><\/p>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">Here, we need to calculate the value of N.<\/span><\/p>\n<p><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><span style=\"font-weight: 400;\">The normal force is equal to the sum of the forces acting on an object <\/span><i><span style=\"font-weight: 400;\">perpendicular<\/span><\/i><span style=\"font-weight: 400;\"> to the surface it is in contact with. In this case, the only force acting perpendicular to the road is gravity. This means that the normal force is equal to the weight of the car. We can calculate the weight of the car using the following equation:<\/span><\/span><\/p>\n<p style=\"text-align: center;\"><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><strong><span style=\"font-size: 14pt;\">W = m*g<\/span><\/strong><\/span><\/p>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">Since we have all the needed information, we can solve for the forces as follows:<\/span><\/p>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>Gravity<\/b><\/span><\/li>\n<\/ul>\n<p style=\"text-align: center;\"><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><strong><span style=\"font-size: 14pt;\">F<sub>g<\/sub> = m*g = (1000 kg)(9.81 m\/s2) = 9810 N<\/span><\/strong><\/span><\/p>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>Force exerted by the road<\/b><\/span><\/li>\n<\/ul>\n<p style=\"text-align: center;\"><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><strong><span style=\"font-size: 14pt;\">F<sub>r <\/sub>= m*a = (1000 kg)(2 m\/s<sup>2<\/sup>) = 2000 N<\/span><\/strong><\/span><\/p>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>Friction<\/b><\/span><\/li>\n<\/ul>\n<p style=\"text-align: center;\"><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><strong><span style=\"font-size: 14pt;\">F<sub>f <\/sub>= \u00b5N = (0.5)(9810 N) = 4905 N<\/span><\/strong><\/span><\/p>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>Force exerted by the engine<\/b><\/span><\/li>\n<\/ul>\n<p style=\"text-align: center;\"><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><strong><span style=\"font-size: 14pt;\">F<sub>e<\/sub> = m*a = (1000 kg)(2 m\/s<sup>2<\/sup>) = 2000 N<\/span><\/strong><\/span><\/p>\n<h3><span class=\"ez-toc-section\" id=\"Problem_2\"><\/span><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><b>Problem 2<\/b><\/span><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><span style=\"font-weight: 400;\">A box is being pulled across the floor by a rope. The box has a mass of 4 kg and is being pulled with a force of 10 N. The coefficient of friction between the box and the floor is 0.4. <\/span><b>What is the acceleration of the box?<\/b><\/span><\/p>\n<p><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>Solution<\/b><\/span><\/p>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">First, let\u2019s create a free-body diagram of the situation.<\/span><\/p>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">As we can see, two forces are acting on the box: the force exerted by the rope and friction. We know that the box has a mass of 4 kg and is being pulled with a force of 10 N. This means that the sum of the forces must be equal to the mass of the box times the acceleration.<\/span><\/p>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">Now, let\u2019s label each force and write down the equations we need to solve for each one.<\/span><\/p>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>Force exerted by the rope<\/b><\/span><\/li>\n<\/ul>\n<p style=\"text-align: center;\"><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><strong><span style=\"font-size: 14pt;\">F<sub>r<\/sub> = m*a<\/span><\/strong><\/span><\/p>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>Friction<\/b><\/span><\/li>\n<\/ul>\n<p style=\"text-align: center;\"><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><strong><span style=\"font-size: 14pt;\">F<sub>f<\/sub> = \u00b5N<\/span><\/strong><\/span><\/p>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">To solve for these forces, we will need to know the values of m, a, \u00b5, and N. We are given m and Fr, but we will need to calculate \u00b5, N, and a. In this example, we are given the value of \u00b5, and we still need to calculate the values of N and a.<\/span><\/p>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">The normal force is equal to the sum of the forces acting on an object perpendicular to the surface it is in contact with. In this case, the only force acting perpendicular to the floor is gravity. This means that the normal force is equal to the weight of the box. We can calculate the weight of the box using the following equation:<\/span><\/p>\n<p style=\"text-align: center;\"><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><strong><span style=\"font-size: 14pt;\">W = m*g<\/span><\/strong><\/span><\/p>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">Now that we have all of the information we need, we can solve for the forces.<\/span><\/p>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>Force exerted by the rope<\/b><\/span><\/li>\n<\/ul>\n<p style=\"text-align: center;\"><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><strong><span style=\"font-size: 14pt;\">F<sub>r<\/sub> = m*a = (4 kg)(10 N) = 40 N<\/span><\/strong><\/span><\/p>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>Friction<\/b><\/span><\/li>\n<\/ul>\n<p style=\"text-align: center;\"><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><strong><span style=\"font-size: 14pt;\">F<sub>f<\/sub> = \u00b5N = (0.4)(40 N) = 16 N<\/span><\/strong><\/span><\/p>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">As we can see, the two forces acting on the box are the force exerted by the rope and friction. The magnitude of each force is 40 N and 16 N respectively. Since the sum of the forces must be equal to the mass of the box times the acceleration, we can solve for a using the following equation:<\/span><\/p>\n<p style=\"text-align: center;\"><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><strong><span style=\"font-size: 14pt;\">a = (F)\/(m)<\/span><\/strong><\/span><\/p>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">where<\/span><\/p>\n<ul>\n<li><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>F:<\/b><span style=\"font-weight: 400;\"> the sum of the forces, and<\/span><\/span><\/li>\n<li><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\"><b>m:<\/b><span style=\"font-weight: 400;\"> the mass of the box.<\/span><\/span><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">&#8211; Acceleration of the box is given by<\/span><\/p>\n<p style=\"text-align: center;\"><span style=\"font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">a = <span style=\"font-weight: 400;\">(40 N + 16 N)\/(4 kg)<\/span> = 12 m\/s<sup>2<\/sup><\/span><\/p>\n<h2><span class=\"ez-toc-section\" id=\"Advantages_of_Free-Body_Diagrams\"><\/span><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><b>Advantages of Free-Body Diagrams<\/b><\/span><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">There are many advantages to using free-body diagrams, including:<\/span><\/p>\n<ol>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">They can be used to simplify complex real-world scenarios.<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">They can be used to predict how an object will move under given circumstances.<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">They can be used to identify all of the external forces acting on an object.<\/span><\/li>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">They can be used to determine the net force acting on an object.<\/span><\/li>\n<\/ol>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">The net force is the vector sum of all of the external forces acting on an object. It is represented by the arrow in the free-body diagram. The direction of the arrow indicates the direction of the net force, and the length of the arrow indicates the magnitude, or strength, of the net force.<\/span><\/p>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">FBDs can be used to solve problems involving both linear and rotational motion. In addition, they can be used to analyze static situations in which an object is not moving. Free-body diagrams are a valuable tool for engineers and physicists, as they can be used to simplify complex problems and to understand the underlying principles of motion.<\/span><\/p>\n<p><span style=\"font-weight: 400; font-size: 14pt; font-family: tahoma, arial, helvetica, sans-serif;\">In summary, free-body diagrams are powerful tools that can be used to solve problems and to understand complex systems. The <a href=\"https:\/\/praxilabs.com\/\">3D virtual lab<\/a>s of PraxiLabs now offer you the opportunity to try out its free-body diagram experiments for free. Don&#8217;t hesitate!<\/span><\/p>\n<p style=\"text-align: center;\"><span style=\"font-family: tahoma, arial, helvetica, sans-serif;\"><strong><a class=\"maxbutton-3 maxbutton\" href=\"https:\/\/praxilabs.com\/en\/request-free-demo\"><span class='mb-text'>Request A Demo Now For Free Virtual Experiments!<\/span><\/a><\/strong><\/span><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Have you ever wondered how physicists create free-body diagrams? What about economists or biologists? All of these professionals use specific symbols to chart the motion of an object. The importance and virality of free-body diagrams (FBD) in physics are beyond description. Free-body diagrams emerged since Newton\u2019s laws of motion stretched out to include many forms &hellip;<\/p>\n","protected":false},"author":11,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_lmt_disableupdate":"no","_lmt_disable":"no","footnotes":""},"categories":[4],"tags":[],"class_list":["post-2117","post","type-post","status-publish","format-standard","","category-physics"],"modified_by":"Muhamed Elmesery","_links":{"self":[{"href":"https:\/\/praxilabs.com\/en\/blog\/wp-json\/wp\/v2\/posts\/2117","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/praxilabs.com\/en\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/praxilabs.com\/en\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/praxilabs.com\/en\/blog\/wp-json\/wp\/v2\/users\/11"}],"replies":[{"embeddable":true,"href":"https:\/\/praxilabs.com\/en\/blog\/wp-json\/wp\/v2\/comments?post=2117"}],"version-history":[{"count":11,"href":"https:\/\/praxilabs.com\/en\/blog\/wp-json\/wp\/v2\/posts\/2117\/revisions"}],"predecessor-version":[{"id":5442,"href":"https:\/\/praxilabs.com\/en\/blog\/wp-json\/wp\/v2\/posts\/2117\/revisions\/5442"}],"wp:attachment":[{"href":"https:\/\/praxilabs.com\/en\/blog\/wp-json\/wp\/v2\/media?parent=2117"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/praxilabs.com\/en\/blog\/wp-json\/wp\/v2\/categories?post=2117"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/praxilabs.com\/en\/blog\/wp-json\/wp\/v2\/tags?post=2117"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}